The sum of the digits of a two digit number is 9 . Also nine this number is twice the number obtained by reversing the order of the digits. Find the number
Answers
Answered by
15
ANSWER:
- Original number = 18
GIVEN:
- sum of the digits of a two digit number is 9 .
- Nine times this number is twice the number obtained by reversing the order of the digits.
TO FIND:
Original number
SOLUTION:
- Let the digit at tens place be 'x'
- Let the digit at once place be 'y'
Original number= 10x+y
Case 1
Case 2
REVERSED NUMBER = 10y+x
Putting : y = 8x in eq (i)
Putting x= 1 in eq(ii)
ORIGINAL NUMBER = 10x+y
= 10*1 +8
= 18
Answered by
19
Given :
- The sum of the digits of a two digit number is 9.
- Also nine *times* this number is twice the number obtained by reversing the order of the digits.
To Find :
- The original two digit number.
Solution :
Let the digit at the tens place be x.
Let the digit at the units place be y.
Original Number = 10x+y
Case 1 :
The sum of the ten's digit and units digit is 9.
Equation :
Case 2 :
9 times the original number is twice the number obtained by reversing the digits order.
Reversed Number = 10y + x
Equation :
Substitute, y = 8 in equation (1),
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