☃⛄☕▁ ▂ ▄ ▅ ▆ ▇ █ The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number. █ ▇ ▆ ▅ ▄ ▂ ▁☕☃⛄
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Answers
Step-by-step explanation:
The Number Is 18....so if We Add 1,8 = 9
By Interchanging Thai Digits We Get 81...
Which Is 18 ×9 = 81 × 2..
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Answer:
Given :-
The sum of digits f a two digit number is 9.
Also nine times this number is twice the number obtained by reversing the order of digit.
To Find :-
The Number
Solution :-
Let the unit digit and tens digits of the number be x and y
Number = 10y + x
Number after reversing the digits = 10x + y
According to the question,
⇒ x + y = 9 ... (i)
⇒ 9(10y + x) = 2(10x + y)
⇒ 88y - 11x = 0
⇒ -x + 8y =0 ... (ii)
Adding equation (i) and (ii), we get
⇒ 9y = 9
⇒ y = 1 ... (iii)
Putting the value in equation (i), we get
⇒ x = 8
Hence, the number is 10y + x = 10 × 1 + 8 = 18.