Question

The sum of the digits of a two-digit number is 9. Also, nine times this

number is twice the number obtained by reversing the order of the digits.

Find the number.​

Answer 1

Answer:

hahahaha

Step-by-step explanation:

kitna aacha question hai nice

Answer 2

Given:-

• The sum of the digits of a two-digit number is 9.
• Nine times number is twice the number obtained by reversing the order of the digits.

To find:-

• Find the number.?

Solutions:-

• Let the digits at ten's place be x
• Let the digits at unit's place be y.

The sum of the digits of a two-digit number is 9.

=> x + y = 9

=> x = 9 - y .........(i).

Nine times number is twice the number obtained by reversing the order of the digits.

Reversed number => 10x + y

9(original number) = 2(Reversed number)

=> 9(10x + y) = 2(10y + x)

=> 90x + 9y = 20y + 2x

=> 90x - 2x = 20y - 9y

=> 88x = 11y

Putting the value of x from Eq (i) in Eq (ii).

=> 88(9 - y) = 11y

=> 792 - 88y = 11y

=> 792 = 11y + 88y

=> 792 = 99y

=> 792/99 = y

=> y = 8

Putting the value of y in Eq (i).

=> x = 9 - y

=> x = 9 - 8

=> x = 1

So, Number => 10x + y

=> 10(1) + 8

=> 10 + 8

=> 18

Hence, the number obtained is 18.