Question

the sum of the digits of a two digit number is 9 also nine times this number is twice the number obtained by reversing the order of the digits find the number ​

Answer 1

Answer:

10a+b is the number(say)

given

9(10a+b) =2(10b+a)

so 88a-11b=0 so 88a=11b

8a=b

so

a+8a=9

a=1

b=8

the number is 18