Math, asked by jahnavi2005, 11 months ago

The sum of the digits of a two digit number is 9 .if 27 is added to it ,the digits of the numbers get reversed . The number is

Answers

Answered by GulabLachman
5

Given: The sum of the digits of a two digit number is 9. If 27 is added to it ,the digits of the numbers get reversed.

To find: The number

Solution: Let the digits of the two digit number be a and b where a is tens digit and b is ones digit.

Since the sum of digits is 9, therefore the equation can be written as:

a+b= 9 -------(i)

The value of any number whose tens and ones digit are known can be written as

= 10( tens digit) + ones digit

= 10a + b

On reversing the number, a becomes the one digit and b becomes the tens digit.

Therefore, the number can be written as

= 10b+a

Now, the number is reversed when 27 is added to it. Therefore,

10a+b +27 = 10b+a

=> 10a-a + b-10b = -27

=> 9a - 9b = -27

=> 9(a-b) = -27

=> a-b = -27/9

=> a-b = -3--------(ii)

Adding (i) and (ii),

a +b + a - b = 9-3

=> 2a = 6

=> a = 6/2

=> a = 3

Using a = 3 in equation (ii),

3-b= -3

=> -b = -3-3

=> -b = -6

=> b = 6

Therefore, the number

= 10a+b

= 10(3) + 6

= 30+6

= 36

On adding 27 to 36, the sum comes out to be 63 which is the number that we get on reversing the digits of 36.

Therefore, the number is 36.

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