The sum of the digits of a two-digit number is 9. If
27 is added to it, the digits of the number get
reversed. The number is
(1) 25 (2) 72 (3) 63 (4) 36
Answers
Solution :
The sum of the digits of a two digit number is 9. If the 27 is added to it, the digit of the number get reversed.
The number.
Let the ten's digit place be r
Let the one's digit place be m
So;
A/q
&
Putting the value of r in equation (1),we get;
Thus;
The original number = 10r + m
The original number = 10(3) + 6
The original number = 30 + 6 = 36.
Option. 4). 36 is the correct option
Given :
- The sum of the digits of a two digits number is 9.
- 27 is added to it, the digits of the number get reversed.
To find :
- The new number =?
Step-by-step explanation:
Let the ones digit number of two digits of the number be x.
Then, the ten 's digit number of the two digit number be y.
Therefore, two-digit number is = 10x + y
And, the reversed number = 10y + x
According to the question :
➟ x + y = 9
➟ y = 9 – x ..... (1)
It is given that :
➟ 10y + x - 10x – y = 27
➟ 9y – 9x = 27
➟ 9(y - x) = 27
➟ y - x = 27/9
➟ y – x = 3 ..... (2)
Substitute the value of y from eq (1) in eq. (2)
➟ 9 – x – x = 3
➟ 9 – 2x = 3
➟ - 2x = 3 - 9
➟ - 2x = - 6
➟ 2x = 6
➟ x = 6/2
➟ x = 3
Hence, x = 3
So, y = 9 – x = 9 – 3 = 6