Question

the sum of the digits of a two digit number is 9,if 27 is added to it.the digit numbers get reversed .the number is

Answer 1

Step-by-step explanation:

Let the digit at ones place be x

Given,

the sum of digits=9

Therefore,

The digit at tens place=9-x

Thus,

The original number=10×(9-x)+x

=90-10x+x

=90-9x

New number by interchanging the number=10x+(9-x)

= 9x + 9

New number-Original number=27

(9x+9)-(90-9x)=27

9x+9-90-9x =27

18x-81 =27

18x =27+81

18x =108

x = 108/18

=6

The digit at ones place=6

The digit at tens place=9-6=3

The original number=36

Hope this helps you!!!!!!!!!