Question

The sum of the digits of a two digit number is 9.If 27 is added to it,thte digits of the numbers get reversed,then the number is___________

Answer 1

Answer:

36

Step-by-step explanation:

Let the unit digit number be x

the tens digit number be 9-x

The original number = 10(9-x)+x

= 90-10x+x

=90-9x

Reversing number = 10x+(9-x)

=10x+9-x

=9x+9

then

According To Problem

Original number+27=Reversing number

90-9x+27=9x+9

117-9x=9x+9

-9x-9x=9-117

-18x = -108

x= -108/-18

x=6

then

Original number=90-9x

=90-9*6

=90-54

=36

Hope it is helpful.

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Answer 2

$\bf\red{\underline{HERE\: IS \:YOUR\: ANSER}}$

To find:

The number

$\bf\green{\boxed{SOLUTION}}$

$Let the number=10x+y$

$and reversed no.=10y+x$

$\bf\large\pink{\underline{A.T.Q}}$

$x+y=9..........i)$

$(10x+y)+27=10y+x$

$10x-x+y-10y=-27$

$9x-9y=-27$

$x-y=-3.........ii)$

From equation i)&ii),we get

$x+y=9$

$<u>x-y=-3</u>$

$2x=6$

$\bf\large\green{\boxed{x=3}}$

putting value of x in equation i),we get

$\bf\large\green{\boxed{y=6}}$

$Number=10x+y$

$\bf\large\bold\green{\boxed{=36}}$

$\bf\large\orange{\boxed{MARK\:AS\:BRAINLIEST}}$