Question

The sum of the digits of a two digit number is 9 if 27 is added to it the digits of the numbers get reversed find the number

Answer 1

Let x be the digit at ones place and y be the digit at tens place. Then 10x+y is the number.

According to the conditions,

x+y=9.........(i)
10x+y+27=10y+x
10x-x=10y-y-27
9x-9y=-27
Dividing by 9
x-y= -3..........(ii)

Solving (i) & (ii)

x+y=9
x-y= -3
..............
2x=6
x=3

Substituting x=3 in equation (i)

y=6

Therefore the digit is 10x+y= 10*3+6=36

Hope this helps.....

Answer 2

Here is your solution

Given :-

The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .

Now

Let ,

x and y are the two digits of a two-digit number.

The two-digit number = 10x + y

reversed number = 10y + x


x + y = 9 ------------1

A/q

10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2

Substract equation 2 from equation 1

2x = 6

x = 3✔


y = 9 - x
y= 9 - 3
y= 6✔


The two digit number = 10x + y = (10 × 3) + 6 = 36.

Hope it helps you