Question

the sum of the digits of a two-digit number is 9. if 27 is subtracted from the number, the digit get reversed. find the number

Answer 1

Let us assume, x and y are the two digits of the two-digit number
Therefore, the two-digit number = 10x + y  and reversed number = 10y + x
Given:
x + y = 9 -------------1
also given:
10x + y - 27 = 10y + x9x - 9y = 27x - y = 3 --------------2
Adding equation 1 and equation 2
2x = 12x = 6
Therefore, y = 9 - x = 9 - 6 = 3
The two-digit number = 10x + y = 10*6 + 3 = 63

Answer 2

Here is your solution

Given :-

The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .

Now

Let ,

x and y are the two digits of a two-digit number.

The two-digit number = 10x + y

reversed number = 10y + x


x + y = 9 ------------1

A/q

10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2

Substract equation 2 from equation 1

2x = 6

x = 3✔


y = 9 - x
y= 9 - 3
y= 6✔


The two digit number = 10x + y = (10 × 3) + 6 = 36.

Hope it helps you