the sum of the digits of a two digit number is 9 if 27 is subtracted from the number the digits are reversed them find the number
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Answered by
1
i hope the answer is 45
sachin5763:
45 if we substract 27 in thatwe get 18 if we add 1+8 is 9 if 18 is reverse 81 s answer if we add 8+1 =9 so the number was 45
Ohh.... but little bit I am confused.... can u send a Papper ans
ok
bro
Answered by
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Here is your solution
Given :-
The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .
Now
Let ,
x and y are the two digits of a two-digit number.
The two-digit number = 10x + y
reversed number = 10y + x
x + y = 9 ------------1
A/q
10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2
Substract equation 2 from equation 1
2x = 6
x = 3✔
y = 9 - x
y= 9 - 3
y= 6✔
The two digit number = 10x + y = (10 × 3) + 6 = 36.
Hope it helps you
Given :-
The sum of the digits of a two digit number is 9.
if 27 is added to it , the digits of the number gets reversed .
Now
Let ,
x and y are the two digits of a two-digit number.
The two-digit number = 10x + y
reversed number = 10y + x
x + y = 9 ------------1
A/q
10x + y + 27 = 10y + x
9y - 9x = 27
y - x = 3 -----------2
Substract equation 2 from equation 1
2x = 6
x = 3✔
y = 9 - x
y= 9 - 3
y= 6✔
The two digit number = 10x + y = (10 × 3) + 6 = 36.
Hope it helps you
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