the sum of the digits of a two digit number is 9 if 9 is added to the number formed by reversing the digits then the result is thrice the original number find the original number
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Answer:
let the digit place be x
the digit in ten's place be=9-x
the number formed on reversing is 10x+(9-x)i.e,
9x+9
9x+9=9+90-9x
9x+9x=99
18x=99
Step-by-step explanation:
divide and see what number is coming then substitute 9-x reverse the number
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