Math, asked by Aditya727452, 9 months ago

The sum of the digits of a two-digit number is 9. If the digits are interchanged, the number obtained exceeds the original number by 27. Find the number.​

Answers

Answered by dhaval211004
2

Answer:

36

Step-by-step explanation:

Let x and y be digits of the no.

x + y =9 ......eq 1

the original no. is

10x + y

according to question

10x + y + 27 = 10y + x

9y - 9x = 27

y - x = 3 .......eq 2

adding eq1 and eq2

-x + y = 3

+

x + y = 9

2y = 12

y=6

now

x+y=9

x=3

hence the required no. is 36

Answered by jyotivicky2006
1

Answer:

answer is 36

Step-by-step explanation:

let let the numberat the tens place be x and that at once place be y the the sum of the digits in a two digit number is 9. the number obtained by interchange the digit exceeds the the original number 27 does the number is 36

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