Question

- The sum of the digits of a two-digit number is 9. If the digits are interchanged, the number obtained
exceeds the original number by 27. Find the number.
-. The digit at the tens place of a two-digit number is four times that is the unitr naon If the
2-​

Answer 1

Answer:

ANSWER

Let the two digit number be 10x+y

Given that the sum of the digits is 9

x+y=9------------------(1))

Given that the number obtained by interchanging the digits exceeds the given number by 27

10y+x=10x+y+27

9x−9y=−27

taking 9 as common

x−y=−3---------------------(2)

Adding equation 1 and 2

x+y=9

x−y=−3

2x=6

x=3

3+y=9

y=6

The number is 10x+y is 36.