Question

The sum of the digits of a two digit number is 9. the digit obtained by increasing the digit in tens place by Unity is one ninth of the number, then the number is

Answer 1

Let’s say x is the unit digit and y is the tenth digit.

y+x = 9 -> y=9-x

10x+y = 10y+x+27

10x+9-x = 10(9-x)+x+27

10x+9-x = 90–10x+x+27

18x = 108

x = 6

so y = 3

let’s check

63 - 39 =27

27 = 27 (correct)

Answer 2

I guess it is 6 and 3 as A and B respectively