Question

the sum of the digits of a two digit number is 9. the number formed by reversing the digits is 45 more than the original number. find the original number.​

Answer 1

Answer:

please refer to the attachment

I hope it would help you

thank you

Answer 2

Step-by-step explanation:

let the digit on the ones place be x

so, the digit on the tenths place= 9-x

then, the number= 10(9-x) + x

On reversing the no. we get =[ 10(9-x) /10]+ 10x = (9-x) +10x

A.T.Q

(9-x) +10x = 10(9-x) +x+ 45

9 - x +10x = 90 - 10 x +x + 45

9 + 9x = 135 - 9x

18x = 126

x = 7

Therefore, the no. =10(9-x) + x

=10(9-7) + 7

=20+ 7

=27