the sum of the digits of a two digit number is 9. the number formed by reversing the digits is 45 more than the original number. find the original number.
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Step-by-step explanation:
let the digit on the ones place be x
so, the digit on the tenths place= 9-x
then, the number= 10(9-x) + x
On reversing the no. we get =[ 10(9-x) /10]+ 10x = (9-x) +10x
A.T.Q
(9-x) +10x = 10(9-x) +x+ 45
9 - x +10x = 90 - 10 x +x + 45
9 + 9x = 135 - 9x
18x = 126
x = 7
Therefore, the no. =10(9-x) + x
=10(9-7) + 7
=20+ 7
=27
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