Question

the sum of the digits of a two-digit number is 9 the number obtained by interchanging its digit is 9 less than thrice the original number find the number​

Answer 1

Answer:

Step-by-step explanation:

Let the no be 10x + y

X + y= 9......i => x= 9- y

10y + x +9 = 3(10x + y)

10y + 9 - y+9 = 3{10(9-y) + y}

9y+18=3{90- 10y +y}

3y +6= 90-9y

12y=84

Y=7

& x =9-7=2

Thus, the no is 10x2+ 7=27.