Question

The sum of the digits of a two digit number is 9. The number obtained by reversing the order of digits of the given number exceeds the given number by 27. Find the given number. In liniar equations in two variable

Answer 1

Step-by-step explanation:

Let the two digit number be 10x+y

Given that the sum of the digits is 9

x+y=9------------------(1))

Given that the number obtained by interchanging the digits exceeds the given number by 27

10y+x=10x+y+27

9x−9y=−27

taking 9 as common

x−y=−3---------------------(2)

Adding equation 1 and 2

x+y=9

x−y=−3

2x=6

x=3

3+y=9

y=6

The number is 10x+y is 36.