Question

the sum of the digits of a two-digit number is 9. the number formed my reversing the digits is 15 more than the original number. find the original number.
please answer it quickly. I will mark him/her as Brainliest answer​

Answer 1

Let the unit's place=x

Then the ten's place=15−x

∴ original number=10(15−x)+x=150−10x+x=150−9x

By reversing the digits, we get

New number=10x+(15−x)=10x+15−x=9x−15

According to the problem,

original number−New number=27

⇒150−9x−9x+15=27

⇒−18x+165=27

⇒−18x=27−165=−108

⇒x=
−18
−108
​
=6

Hence original number=150−9x=150−9×6=150−54=96

Hope it helps you