The sum of the digits of a two-digit number is equal to 1/8 of the number. If the digits of the number are reversed , the new number is 45 less than the original number. Find the number.
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10x+y=1/8
10y+x=45-10x-y
10y+x=45-10x-y
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The number is 72 solution is in photograph
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MakutoShiedo:
Thank u sooooo much dear
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