Question

the sum of the digits of a two digit number is equal to one seventh of the number.if the number obtained by reversing the digits is 27 less than the original number.find the original number

Answer 1

Answer:

63

Step-by-step explanation:

Let the ones digit be x and tens digit be y

Original number=10*T+U=10y+x

Reversed digits:

T=x

U=y

New number=10x+y

ATQ-

10x+y=10y+x-27

9x-9y=-27

9y-9x=27

9(y-x)=9*3

y-x=3

y=3+x

Also, x+y=1/7*(10y+x)

7x+7y=10y+x

6x=3y

2x=y

2x=3+x

x=3

y=3+x=3+3

y=6

Original number

=10y+x

=10*6+3

=60+3

=63