Question

The sum of the digits of a two digit number is one-fourth of the number and the number
obtained by interchanging the digits exceeds the original number by 36. Find the original
number. (Ans.: 48) ​

Answer 1

Answer:Original number=xy

their sum,   x+y=10...........(1)

on interchanging the number

(10y+x)=(10x+y)+36

9y-9x=36

y-x=4........................(2)

adding (1) & (2) we get

2y=14

y=7

putting the value of y in (1) we get

x=3

the original number is xy i.e. 37

Step-by-step explanation:

Answer 2

Answer:

the previous one is correct