Question

the sum of the digits of a two digit numbers is 10 . the number obtained by interchanging the digits exceeds the original number ?

Answer 1

Answer:

Firstly we have rewrite the word problem into Mathematical form:

Let's assume :

x = the 10's digits

y = units

Then the original number:

10x + y = two digit number

Now lets write down what's given in the problem:

x + y = 10

Re-written as: y= 10 -x...

Step-by-step explanation:

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Answer 2

Let the tens place digit be a

And Unit place digit be b

a + b = 10 ---(1)

10a + b + 36 = 10b + a

=> 9a - 9b = - 36

=> a - b = - 4 ----(2)

Adding equation 1 and 2, we get

2a = 6

a = 3

Now, On putting the value of a in equation 1, we get

b = 7

Required number = 37