The sum of the digits of a two digit numbers is 7. If we add 45 to the number, the
digits are interchanged. Find the number.
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Let ,
Ten's digit of a number = " x "
Unit's digit of a number = " y "
Number = " 10x + y "
According to the question ,
x + y = 7 --- (i)
and
10x + y + 45 = 10y + x
9x - 9y = -45
x - y = -5 --- (ii)
Adding eq (i) and eq (ii) , we obtain
x + y + x - y = 7 + (-5)
2x = 2
x = 2/2
x = 1
Put x = 1 in eq (i) , we get
1 + y = 7
y = 6
∴ The number is 16
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