Question

the sum of the digits of a two-digit reimber is 9. Also, 9 time this number is
twire the number obtained by
reversing the order of the digits.
find the number​

Answer 1

Answer:

The number is 18.

Step-by-step explanation:

Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9-----(I)

9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.