Question

the sum of the digits of a two digits number is 10 and the digits at units place is 2/3rd of the digits at tens place. find the number.

Answer 1

number is 64  hope this helps

Answer 2

Answer:

Let the number be 'x' and 'y'.

Hence x + y = 10

x = 10 - y ....(1)

According to the question,

x = 2/3 × y .....(2)

Using cross multiplication method,

3x = 2y

3(10 - y) = 2y

30 - 3y = 2y

- 3y - 2y = - 30

- 5y = - 30

$y = \cancel{ \frac{ -30}{ - </strong><strong>5</strong><strong>} }</strong><strong> </strong><strong> </strong><strong>$ = 6

Put y value in equation in (1)

x = 10 - y

x = 10 - 6

x = 4.