Question

The sum of the digits of a two-digits Number is 10.The number formed by reversing the digits is 18 less than the original number. Find the original number. ​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

64

Step-by-step explanation:

Let the digit at the ones place be x.

the digit at tens place be y.

sum = 10.

=> x+y= 10.

=> y= 10 - x.

Therefore,

let the digit at tens place be ( 10 - x ).

So, as it is at tens place it will be multiplied with 10.

The original no. = 10 ( 10 - x ) + x.

The no. formed by reversing the digits is 18 less than the original number.

So,

According to the question,

=> 10 ( 10 - x ) + x - 18 = 10x + 10 - x

=> 100 - 10x + x - 18 = 10x - x + 10

=> -10x + x - 10 x + x = 10 - 100 + 18

=> -20x + 2x = - 72

=> -18x = -72

=> x = -72/-18

=> x = 4.

Hence, the original no. is 10 ( 10 - x ) + x

=>( 100 - 40 )+ 4

=> 60 + 4

=> 64.