the sum of the digits of a two digits number is 12.if the new number formed by reversing the digits is greater than the original number by 18,find the original number. check your solution. answer doo bhai and behen ??????
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Step-by-step explanation:
Answer:
57
Step-by-step explanation:
let the unit digit = a
and tens digit = b
the number formed = 10b+a
the reverse number = 10a+b
given,
a+b=12 ----(1)
and
(10a+b) - (10b+a) = 18
=> 9a-9b=18
=> a-b=2 ----(2)
adding (1) and (2),
2a = 14
=> a = 7
putting value of a in (1),
7+b=12
=> b = 5
the number = 10b+a = 10×5+7 = 57
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