The sum of the digits of a two-digits number is 14. If 36 is subtracted from the numbers, the places of the digits are reversed. Find the numbers
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the number is 95 whose digits sum is 14 n when we subtract 36 frm it we get 59
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let x and y be two digits and the original number be 10x+y (since x in tenth place and y in first place )
Now Given
x+y = 14 ......... (i)
so the reversed number be 10y+x
Now,
10y+x= (10x+y)-36
On simplifying , x-y= 4....... (ii)
Solving (i) and (ii)
y= 5 and x= 9
so the numbers (10×9+5) = 95 and reversed number will be ( 10×5+9)= 59
Now Given
x+y = 14 ......... (i)
so the reversed number be 10y+x
Now,
10y+x= (10x+y)-36
On simplifying , x-y= 4....... (ii)
Solving (i) and (ii)
y= 5 and x= 9
so the numbers (10×9+5) = 95 and reversed number will be ( 10×5+9)= 59
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