Question

the sum of the digits of a two digits number is 15 if the number formed by reversing the digita is 27 less than the original number, find the original number

please solve the question if you don't know don't answer​

Answer 1

Answer:

Step-by-step explanation:

let tens digit of the original number be x

so original number,

10(x) + (15-x)  

reversing digits mean

10(15-x) + x

therefore

[10(x) + (15-x)]-[10(15-x)+x] = 27

or  10x + 15-x - 150+10x-x = 27

or 10x + 10x + 15 - 150 -x - x = 27

or 20x - 135 -2x = 27

or 18x - 135 = 27

or 18x = 27 + 135

or 18x = 162

or x = 162/18

or x = 9

original number = 10(x) + (15-x)  

                             = 10(9) + (15-9)

                             = 90+6

                             = 96

Answer 2

Answer:

Original number is 96.

Step-by-step explanation:

Let two digit number are xy or (10x+y)  [:ex: 59=(5*10+9) ]

then x+y=15 ;...........(i)

by reversing the digits numer wiil be (10y+x)

then according to question

(10x+y)-27=(10y+x)

10x+y-10y-x=27

9x-9y=27

x-y=3   ............(ii)

Add (i) and (ii)

x+y+x-y=15+3

2x=18

x=9

y=15-x=15-9=6

So, original number is (10x+y)=9*10+6=96