The sum of the digits of a two digits number is 15 .The number obtained by interchanging the digits exceeds the given number by 9.The number is
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Answer:
78
Step-by-step explanation:
let the digit in units place be x and the digit in tens place be y.
then,the original number is 10y+x
the number obtained by interchanging digits=10x+y
cond. 1:
given,sum of digits=15
⇒ x+y=15 ---------- (1)
cond.2:
10x+y=10y+x+9
9x-9y=9
x-y=1 -------------- (2)
solving (1) and (2), [by elimination method]
x+y=15
x-y=1
- + -
--------------
2y=14
y=7
put y=7 in (1),
x=15-7=8
hence,the given number=10y+x=78
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