The sum of the digits of a two digits number is 7 the number obtained by interchanging the digits exceeds the original number by 27 find the no.
Answers
Answer:
Let x = the original ten's digit.
Let y = the original one's digit.
Then 10x + y is the value of the original 2-digit number, and 10y + x is the value of the interchanged 2-digit interchanged number.
The sum of the digits is 7: x + y = 7.
Interchanged number exceeds original number by 27.
10y + x = 10x + y + 27.
Us the substitution method to solve.
A2
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Answer:
Let the first digit = x
Therefore second digit = 7 - x
Number = 10 × (7 - x) + 1 × x
>> 70 - 10x + x
>> 70 - 9x
On interchanging the digits, number becomes = 10 × x + 1 × (7 - x)
>> 9+7x
According to Question:
>> 9 + 7x - (70 - 9x) = 27
>> 9 + 7x - 70 + 9x = 27
>> 18x - 63 = 27
>> 18x = 27 + 63
>> x = 2
Therefore first digit = 2
Number = 10 × 2 + 1 × 5
>> 25
Step-by-step explanation: