Question

the sum of the digits of a two -digits numbers is 15 if the number obtain by reversing the digit is less than the original number by 27 find the original number ​

Answer 1

let units digit of the number be x

let tens of the number be y

Then, the number is 10y+x

given that y+x=15--------1

If we reverse the digits of the number , we obtain a new number which is 10x+y

as per condition,

10y+x-(10x+y)=27

9y-9x=27

y-x=3-------2

eqn.1+eqn.2

2y=18

y=9

x=6

The original number is 96

Answer 2

Answer:

96 is the required number