The sum of the digits of a two digits numbers is 9. The number is eual to 5 times the sum of the digits. Find the numbers.
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Answers
Answer:
The sum of all the two digit numbers which are multiples of 9 is 585...
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Let the tens digit =x
Let the units digit =y
The sum of digits of a two digit number is 5, so x+y=5
When the digits are reversed, the number is 9 more than the original
since x is your tens digits, its value is 10x.
So, yo have the value of your original number 10x+y.
Now, reverse the digits the number =10y+x
So, equation formed =10y+x=(10x+y)=9
⇒10y−y=10x−x+9
⇒9y=9x+9
⇒9y−9x=9
⇒9(y−x)=9
⇒y−x=9/9=1
y−x=1
y+x=5
_________
2y=6
⇒y=6/2
⇒y=3
Put y in y−x=1
3−x=1
−x=1−3
x=2
∴ The original number is 10x+y=10(2)+3=20+3=23.