the sum of the digits of a two digut number is 10 and the digit at unit place is 2/3rd of th the digit at tens place. find the number.
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hey mate here is your answer.
let the no. at tens place be x
A/Q
x+2/3×x=10
x+2x/3 =10
(3x+2x)/3=10
5x/3 =10
5x=30
x=6
NOW,
2/3 of x =4
lets verify
LHS RHS
4+6 10
10 = 10
hence verifed.
therefore the no. = 64
hope it helps you.
let the no. at tens place be x
A/Q
x+2/3×x=10
x+2x/3 =10
(3x+2x)/3=10
5x/3 =10
5x=30
x=6
NOW,
2/3 of x =4
lets verify
LHS RHS
4+6 10
10 = 10
hence verifed.
therefore the no. = 64
hope it helps you.
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