Question

the sum of the digits of a two dugit number is 9. also, nine times this no. is twice the no. obtained by reversing the order of the digits find the no.​

Answer 1

Answer:

x+y=9

9(10x+y)=2(10y+x)

≈90x+y=20y+x

≈90x-x=20y-y

≈89x-19y=0

solving graphically

X=1.6

y=7.4

Answer 2

Let the number be 10x+y

X +y= 9

9(10x+y)=2(10y+x)

90x+9y= 20y+2x

88x=11y

8x=y

Substituting this in x+y=9

X+8x= 9

X=1

Y=8

The number is 18

Please mark my answer as the brainliest