Question

The sum of the digits of a two number is 9.If the number are reversed ,the number is 63 more than the original. Find the number

pls answer this fast​

Answer 1

Answer:

81

Step-by-step explanation:

Dude its very easy...just follow my steps....

ORIGINALLY

Let the units digit be 'a'.

Thus, tens digit = 9-a [as sum is 9]

Thus, Number = 10(9 - a) + a

NOW

As the digit is reversed,

Units digit = 9-a

Tens digit = a

Thus, Number = 10a + (9 - a)

Hence,

A.T.P.

=)Final number = 63 + Original number

=)10a + (9 - a) = 63 + 10(9 - a) + a

=)9a + 9 = 63 + 90 - 10a + a

=)9a + 10a - a = - 63 + 90 - 9

=)18a = 18

=)a = 1

Thus, original number = 10(9-a)+a

= 81

Hope it helps you buddy....

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