The sum of the digits of a2-digit number is 15. If the nub er formed by reversing the digit is less than the original number by 27 fine the original number.
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let ones digit be y, tens digit be x
therefore the number = 10x + y
reversed number = 10y + x
ATQ:
x + y = 15
10y + x + 27 = 10x + y
=> 10x - x + y - 10y = 27
=> 9x - 9y = 27
=>x - y = 3
hence
x + y = 15
x - y = 3
=> 2x = 18
=> x = 9
hence
x + y = 15
9 + y = 15
y = 15 - 9 = 6
hence the original number = 10x + y = 10 x 9 + 6 = 96
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