Question

The sum of the digits of the digits of a two-digit number is 8. If the number formed by reversing the digits is less than the original number
by 18. Find the original number. Answer quicker

Answer 1

Answer:

The number can be 53 or 35

Step-by-step explanation:

Let the numbers be x as ones digit and y as tens digit

Their sum is 8

So, x + y = 8 .......(i)

The number formed

➡️ 10y + x

Interchanging the digits we get :

➡️ 10x - y

According to the question,

$\sf : \implies \: (10y + x) - (10x + y) = 18 \\ \sf : \implies \: 9x - 9y = 18 \\ \sf : \implies \: x - y = 2......(ii)$

Substraction of both the equation :

$\sf \: x + y = 8 \\ \sf { \underline{x - y = 2 }} \\ \sf : \implies \: 2x = 6 \\ \sf : \implies \: x = \frac{6}{2} \\ \sf : \implies \: x = 3 \: ans.$

Substituting the value of x in equation (i) :-

=> x + y = 8

=> 3 + y = 8

=> y = 5

Hence,

The number can be 53 or 35