Question

the sum of the digits of the numbers of two digits is 7. If the digits are reversed, then adding 3 to the new number becomes four time of the original number. What is the original number.​

Answer 1

Answer:

Step-by-step explanation:

Let the nos be x,y

X+ y=7

Y=7-x

10y+ x +3 = 4 (10x+y)

10y +3+x= 40x+4y

39x -6y =3

13x-2y=1

13x-14+2x=1

X=1 y=6 number is 16

Answer 2

Answer:

Let the number be x and y respectively.

The original number wee be 10x + y

According to the question,

x + y = 7 ---(1)

And also when we reversed the digit, and add 3 the no. becomes 4 times the originals therefore, the given statement will be represented as

10 y + x = 4(10x + y) - 3

10y + x = 40x + 4y - 3

13x - 2y = 1 ---(2)

Multiplying equation (1) by (2)

2x + 2y = 14 ---(3)

Adding question (2) & (3), We get

15x = 15

x = 1

Substituting x = 1 in equation (1)

x + y = 7

y = 7 - 1

y = 6

Substituting the value of x and y in original number.

10x + y

10(1) + 6

= 10 + 6

= 16

Therefore, the original number is 16.