Math, asked by manmith14, 10 months ago

the sum of the digits of the two digit no is 9. the number obtained by reversing the order of digits of the given no exceeds the given no by 27. find the no​

Answers

Answered by gjyala1414
0

Answer:

36

Step-by-step explanation:

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Answered by divyajain9b
0

Answer:

answer is 36

Step-by-step explanation:

let the two digit number be 10x +y

so, x +y = 9 (equation 1)

given that the number obtained by interchanging the digit exceeds the given number by 27

10y +x = 10x + y +27

9x-9y = -27

x-y = -3 (taking 9 as common) (equation 2)

adding equation 1 and 2

x+y =9

x-y= -3

2x = 6                                                                                                                                                          

x=3

3+y = 9

y = 6

the number is 10x+y is 36

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