Question

The sum of the digits of the two digit
number is 10. If the number formed by
reversing the digits is greater than the
original number by 18, find the original
number​

Answer 1

Answer:

46

Step-by-step explanation:

let the number in the tens digit be x

so,number in the ones digit is (10-x)

so, number formed=10x+10-x

=9x+10

so, reversed number=10(10-x)+x

=100-9x

according to the question

100 - 9 x -(9x + 10) = 18

100 - 9x - 9x - 10 = 18

90-18x =18

- 18x = 18 - 90

-18x = -72

x=4

so, (4*10)=40+(10-4)=40+6=46