Question

The sum of the digits of the two digit number is 13. the number formed by interchanging digits is 45 more than the original number. find the original number

Answer 1

Let the unit digit be y
And the tens digit be x
So the no formed will be xy

The sum of the digits is 13
So, x+y=13... So x=13-y......(1)
The original no is 10x+y
No obtained by interchanging the digits is 10y+x
Given that the new no is greater than the original one by 45
ATQ
(10x+y)+45=(10y+x)
10x-x=10y-y-45
9x=9y-45
Putting the value of x from (1)..we get
9(13-y)=9y-45
117-9y-9y=45
117-45=9y+9y
72=18y
Y=4

Putting the value of y in (1)..
X=13-y
X=13-4
X=9

So the original no is 10x+y
=10*9+4
=90+4
=94
Hence the no is 94

Hope it helps you... Please mark as brainliest

Answer 2

Answer:

94

Step-by-step explanation:

this answer is 94 and thus you can understand on this answer and choose the answer as brainliest answer