The sum of the digits of the two digit number is 15 if the number is formed by reversing the digit is less then the original number 27 what is the original number
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Let tens digit of the original number be x
so original number,
10(x) + (15-x)
reversing digits mean
10(15-x) + x
therefore
[10(x) + (15-x)]-[10(15-x)+x] = 27
or 10x + 15-x - 150+10x-x = 27
or 10x + 10x + 15 - 150 -x - x = 27
or 20x - 135 -2x = 27
or 18x - 135 = 27
or 18x = 27 + 135
or 18x = 162
or x = 162/18
or x = 9
original number = 10(x) + (15-x)
= 10(9) + (15-9)
= 90+6
= 96
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