the sum of the digits of the two digit number is 15 the number obtained by interchanging the digits is 27 more than the given number find the original number
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let the number be 10x+y.
ATQ,
x+y=15......(1)
x=15-y
10y+x=27+10x+y
Putting the value of x, we get;
10y+15-y=27+150-10y+y
10y+10y-y-y=27-15
20y-2y=12
18y=12
y=2/3
Putting the value of y in equation(1),we get;
x=43/3
original number is 430/9
Plz mark me as brainiest
ATQ,
x+y=15......(1)
x=15-y
10y+x=27+10x+y
Putting the value of x, we get;
10y+15-y=27+150-10y+y
10y+10y-y-y=27-15
20y-2y=12
18y=12
y=2/3
Putting the value of y in equation(1),we get;
x=43/3
original number is 430/9
Plz mark me as brainiest
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