Math, asked by navyakasera, 9 months ago

the sum of the digits of the two- digits number is 12. the number formed by interchanging the digits is greater than the original number by 54 . find the original number......
pls give an explanation
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Answers

Answered by ijalok255
0

Answer:

Step-by-step explanation:

Let the digit at the ten's place be x.

Given : The sum the digits of two digit number is 12.

 

→ the digit at the unit's place = 12 - x

→ Original number = 10x +(12 - x) = 9x + 12  

If the new number formed by reversing the digits is greater than the original number by 54.

[10(12 - x) + x]- [10x +(12 - x)] = 54

 

After solving, we get

x = 3  

 

Therefore original number = 9x + 12 = 9 × 3 + 12  = 39

Answered by harshit2164
0

Answer:

let the number is 10x + y

so digits are x and y

according to question ,

x + y=12

if we interchange digits, number become 10y + x

according to question, (10 y + x)-(10x + y) =54

then 9y - 9x=54

y-x=6

and , we have y+x=12

let us solve these equations,

add both equation, we get 2y=18

y=9, put in any of the equation

we get x=3

so number is 10(3)+6=36

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