the sum of the digits of the two- digits number is 12. the number formed by interchanging the digits is greater than the original number by 54 . find the original number......
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Answers
Answer:
Step-by-step explanation:
Let the digit at the ten's place be x.
Given : The sum the digits of two digit number is 12.
→ the digit at the unit's place = 12 - x
→ Original number = 10x +(12 - x) = 9x + 12
If the new number formed by reversing the digits is greater than the original number by 54.
[10(12 - x) + x]- [10x +(12 - x)] = 54
After solving, we get
x = 3
Therefore original number = 9x + 12 = 9 × 3 + 12 = 39
Answer:
let the number is 10x + y
so digits are x and y
according to question ,
x + y=12
if we interchange digits, number become 10y + x
according to question, (10 y + x)-(10x + y) =54
then 9y - 9x=54
y-x=6
and , we have y+x=12
let us solve these equations,
add both equation, we get 2y=18
y=9, put in any of the equation
we get x=3
so number is 10(3)+6=36