Question

the sum of the digits of two digit number is 12 if 18 is added to it the digit are received find the number​

Answer 1

Step-by-step explanation:

You meant “the digits are reversed; what is the original number?”

The solution can be obtained by letting x be the ‘tens digit’, and y be the unit digit, so that the original number is 10x+y.

Then 10x+y+18=10y+x, because the digits are reversed. This simplifies to 9x+18=9y, or x+2=y. Since the digits add up to 12, x+y=12. Substituting for y yields x+2=12-x, which simplifies to x=5. Then y=7, so the original number is 57. 57+18 = 75.

Answer 2

Answer:

The number is 57.

Step-by-step explanation:

• Given :-
• The sum of the digits of two digit number is 12.
• If 18 is added to it, is added to it, the digits are reversed.

To find :-

• The number.

Solution :-

Let the ten's digit of the number be x and the unit's digit of the number be y.

Then,

• The number = 10x+y

According to the 1st condition,

• The sum of the digits of two digit number is 12.

x+y = 12

→ x = 12-y............(i)

According to the 2nd condition,

• If 18 is added to it, is added to it, the digits are reversed.

10x+y+18=10y+x

→ 10(12-y)+y+18=10y+12-y

→ 120-10y +y +18 = 9y+12

→ 120-9y+18=9y+12

→ -9y-9y = 12-120-18

→ -18y = -126

→ 18y = 126

→ y = 7

Now put y = 7 in eq(i).

x = 12-y

→ x = 12-7

→ x = 5

Therefore,

• The number = 10×5+7 = 57

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