Question

The sum of the digits of two digit number is 12 the number obtained by reversing the order of the rajat of the given number exceeds the given number by 18 find the number

Answer 1

Let the number be 10a+b
now According to the question

a+b=12 ......(i)and

10b+a = (10a+b)+18
9b-9a=18
b-a=2.........(ii)

Adding eq (i) and (ii) we get
2b=14
b=7 and by substituting in (i) we get
a=5

So, the number is 57

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