The sum of the digits of two digit number is 13.If the digits are interchanged and the resulting number is added to the original Number, then we get 143.What is the original number?
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Answer:
The sum of the digits of a two-digit number is 13. If the digits are interchanged, and the resulting number is added to the original number, then we get 143. What is the original number?
Unknown. This question does not have a singularly unique answer. Any one of 49, 58, 67, 76, 85, or 94 can be correct.
In fact, all that is necessary is to know that the two digits sum to 13. Let the tens digit be a , and the units digit be b.
a+b=13
If the original number can be represented with 10a+b , then the reverse of it would be 10b+a . Their sum is 143, so:
10a+b+10b+a=143
⟹11a+11b=143
⟹11a+11b11=14311
...and that results in a+b=13
In other words, no new information is provided from the second part of the question. So what is the “original”number? Well, it's any two digit number where the digits sum to 13.
Step-by-step explanation:
The sum of the digits of a two-digit number is 13. If the digits are interchanged, and the resulting number is added to the original number, then we get 143. What is the original number?
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The sum of the digits of a two-digit number is 13. If the digits are interchanged, and the resulting number is added to the original number, then we get 143. What is the original number?
Unknown. This question does not have a singularly unique answer. Any one of 49, 58, 67, 76, 85, or 94 can be correct.
In fact, all that is necessary is to know that the two digits sum to 13. Let the tens digit be a , and the units digit be b.
a+b=13
If the original number can be represented with 10a+b , then the reverse of it would be 10b+a . Their sum is 143, so:
10a+b+10b+a=143
⟹11a+11b=143
⟹11a+11b11=14311
...and that results in a+b=13
In other words, no new information is provided from the second part of the question. So what is the “original”number? Well, it's any two digit number where the digits sum to 13.