Question

the sum of the digits of two digit number is 15. the number obtained by interchanging the digits exceeds the given number by 9. find the number

Answer 1

#AlexaRousey here!!

Let the number be in form of 10x + y.

According to question,

=) x+y = 15 .. Eq1.

2nd case:

=) 10y + x = 10x + y + 9

=) 10y - y + x - 10x = 9

=) 9y - 9x = 9

=) 9(y-x) = 9

=) y-x = 9/9 = 1 .. Eq2.

Add both eq ;

=) x+y + y-x = 15+1

=) 2y = 16

=) y = 16/2 = 8

Put the value of y in eq1;

=) y + x = 15

=) 8 + x = 15

=) x = 15-8 = 7

Hence number is 10*7 + 8 = 78

Thanks!

Answer 2

Hey MATE!

Check out the image for your solution.

Hope it helps

Hakuna Matata :))